![]() ![]() I forgot to mention that I am running Mac OS X, so the functions may be slightly different from the ones discussed in other answers for the unix/linux shell (hence some of my confusion with sed, awk,and grep). To search for all files with pattern abc: ls -d abc list all files starting with abc- ls -d abc list all files containing -abc- ls -d abc list all files ending with -abc Note that the file extension is relevant for the search results too. I understand the concept of regular expressions clearly, but I get confused between regexes that use different syntax. ls The default directory list utility ls can be used in combination with the shell's wildcards. If a specific order of files is needed, ls grep might be the best.I really should learn how to use sed, awk,and grep, but I keep getting stuck at understanding how to write the regexes. ls has sorting options that are tricky to get right with other commands. I tried testing this by running: grep -i <(ls) This does not work, though nothing happens. A suggestion has been made that I am simply looking for <(ls). I don't know exactly how to do this, but I'm imagining it would be something like: > ls | sed grep -i ls /etc/nataswebpass dictionary.txt Buy I would like to try to solve this exercise not using the semicolon, but perhaps actually use grep that is already there. If not, is there a way to pipe the output of ls to another function (possibly sed) that shows only the ones that I would like? Now I would like to do something that does the following > ls - *.txt ![]() Do you know how to perform this operation? I've read the man page for ls, and I can't find the option to list all that do not match the file selector. The Story Behind grep The grep command is famous in Linux and Unix circles for three reasons. It also works with piped output from other commands. How can I use inverse or negative wildcards when pattern matching in a unix/linux shell? The Linux grep command is a string and pattern matching utility that displays matching lines from multiple files. ![]()
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